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Scanner Is Not Working In Java


Neil Cartmell Ranch Hand Posts: 150 posted 6 years ago Ok i'm now doing it in notepad and it is doing the same thing. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. With this approach you will not confront your problem. http://tekconceptllc.com/not-working/snipmp3-not-working-java.php

How to avoid of that? –blekione Oct 27 '12 at 16:45 1 Or you could be like me and use BufferedReader :) I don't care if it's old school, it Calling nextLine(), will then grab anything else that was entered in the line after the int. Relation of pressure and temperature for an ideal gas at constant volume How to check whether a partition is mounted by UUID? What are options to increase difficulty? http://stackoverflow.com/questions/3236830/scanner-in-java-not-working

Java -version Command Not Working

import java.util.Scanner; class string { public static void main(String a[]){ int a; String s; Scanner scan = new Scanner(System.in); System.out.println("enter a no"); a = scan.nextInt(); System.out.println("no is ="+a); System.out.println("enter a string"); use in.next() instead of in.nextLine(). import java.util.Scanner; public class LoopLock { public static void Looper() { int numb1, numb2, numb3; int Lock1 = 12; int Lock2 = 24; int Lock3 = 48; boolean correct = false;

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Problem is, the program always skips the last question (never letting the user answer 'y' or otherwise. Java Util Scanner Not Working Try it like that: System.out.print("Insert a number: "); int number = input.nextInt(); input.nextLine(); // This line you have to add (It consumes the \n character) System.out.print("Text1: "); String text1 = input.nextLine(); This method will throw an InputMismatchException if conversion to an int was unsuccessful. Utensil that forms meat into cylinders How not to lose confidence in front of supervisor?

Hopefully one day i will have enough knowledge to be the one giving advice! Java Scanner Nextline I input: neil computer says: Hello neil How old are you? VERY basic java 2 Java Scanner why is nextLine() in my code being skipped? 1 scan.nextLine does not work 1 Why System.out.println can't print out a string value (in my particular Not the answer you're looking for?

Java Util Scanner Not Working

Keith Lynn Ranch Hand Posts: 2409 posted 9 years ago Since javac -version doesn't work, that means you're Java compiler is not 1.5. Get More Info This is the exact code. Java -version Command Not Working share|improve this answer answered Sep 4 '12 at 14:09 NominSim 5,74911330 Parsing is not a good solution.... –user1646373 Sep 13 '12 at 14:14 @user1646373 Care to enlighten Import Java.util.scanner Not Working java java.util.scanner share|improve this question edited Aug 23 at 20:28 Pshemo 71.8k1090134 asked Oct 27 '12 at 16:37 blekione 1,177377 3 Related: stackoverflow.com/questions/4708219/… –James P.

When debugging the playing variable is set to "", so there is no input that I can see and I cannot figure out what is being consumed. his comment is here I've been searching around online for other Java tutorials (now have a few good ones plus the Head First Java book) and came across java.util.Scanner in a practical exercise. What Russian letter is this? Relation of pressure and temperature for an ideal gas at constant volume The Art of Word Shaping Is there a class like Optional but for non-optionals? Java Scanner Read String

Did you ever download 1.5? Join them; it only takes a minute: Sign up Java Scanner doesn't work in Processing up vote 5 down vote favorite For an assignment I have due, my group and I I'm impressed how quick you responded –blekione Oct 27 '12 at 16:53 5 @blekione. http://tekconceptllc.com/not-working/simpledateformat-not-working-java.php I'm not so sure it's an error in my code so much as perhaps an error in my system variables somewhere?

The users who voted to close gave this specific reason:"This question was caused by a problem that can no longer be reproduced or a simple typographical error. Scanner Nextline Not Working You're welcome :) –Rohit Jain Oct 27 '12 at 16:58 3 @blekione. But if that's the case, wouldn't the commands javac and java also not be working?

share|improve this answer edited May 30 at 12:08 Ro Yo Mi 10.5k41731 answered May 30 at 11:21 esskay 83 This does not provide an answer to the question.

But Scanner is far from foolproof. I forgot the solution but I will look it up later on. Not the answer you're looking for? Scanner Nextint Wow what a coincidence!

I think a more readable/idiomatic solution would be to call scanner.skip("[\r\n]+") to drop any newline characters after calling nextInt(). it's working as specified. Inconsistent size of parentheses in Latin Modern and Computer Modern more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile navigate here When input.nextLine() executes, it consumes the "end of line" still in the buffer from the first input.

But how can one go around this problem? –Yasky Sep 18 '15 at 15:54 add a comment| up vote 3 down vote This is a common misunderstanding which leads to confusion computer says: What is your name? it look really good, other than do i need to change my if statement to that? Scanner in = new Scanner(System.in); String name; String playing; int age; do { System.out.println("Enter your name"); name = in.next(); System.out.println("Enter your age"); age = in.nextInt(); System.out.println("Play again?"); playing = in.next(); }

Until you get comfortable with how this works, it's likely to cause problems (especially since it probably does not include the current directory "."). "We're kind of on the level of CODE: FIRST CLASS: import java.util.Scanner; class hand { public static void main(String[] args) { tuna opObject = new tuna(); //creating input Scanner input = new Scanner(System.in); //instructions System.out.println("This is an interactive Join them; it only takes a minute: Sign up Scanner in Java not working up vote 2 down vote favorite I'm trying to write a very simple number guessing game (code BrEng and AmEng mobile homes I'm technical referent but I lost the lead for technical decisions Movie involving a cute Blondie that fights a dragon more hot questions lang-java about us

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posted 9 years ago Originally posted by Keith Lynn: Since javac -version doesn't work, that means you're Java compiler is not 1.5. How to replace 8-sided dice with other dice Why do governments not execute or otherwise permanently contain super villains? Also, knowledge of BufferedReader has application elsewhere. asked 3 years ago viewed 2185 times active 3 years ago Upcoming Events 2016 Community Moderator Election ends in 7 days Blog How We Make Money at Stack Overflow: 2016 Edition

Cheers, Nate The very existence of flamethrowers proves that at some time, some where, some place, someone once said to themselves "I'd really like to set those people on fire over Scanner scanner = new Scanner(System.in).useDelimiter("\n"); And for reading the line you should write scanner.next(); share|improve this answer answered May 6 '12 at 6:24 Bhavik Ambani 4,74253872 add a comment| Not the I have tried to make it with if and if else statements but that didn't work either(and yes I was using'.equals' not '==' for the parameters of the if statements). Browse other questions tagged java loops java.util.scanner or ask your own question.

Anupama Sudhakaran Greenhorn Posts: 18 posted 6 years ago Hi i use the next() method from Scanner class for taking input as String. What you want is something like this: import java.util.Scanner; public class Tuna { // Classes should always begin with an uppercase letter // Moved object attributes into method public void options() Brainfuck Interpreter written in x86 Assembly Magnetic effect on AC circuits? Should an arrow for "update" point up or down?